- (A) friction and windage losses
- (B) copper losses
- (C) hysteresis and eddy current losses
- (D) none of the above
Electrical Engineering Mcqs
- (A) reduces weight per kVA
- (B) reduces iron losses
- (C) reduces copper losses
- (D) increases part load efficiency
- (A) primary side
- (B) secondary side
- (C) low voltage side
- (D) high voltage side
- (A) The power factor of the two trans-formers will be different from the power factor of common load
- (B) Incorrect polarity will result in dead short circuit
- (C) The transformers will not share load in proportion to their kVA ratings
- (D) none of the above
- (A) transformers will be overheated
- (B) power factors of both the transformers will be same
- (C) parallel operation will be not possible
- (D) parallel operation will still be possible, but the power factors at which the two transformers operate will be different from the power factor of the common load
- (A) R2/VK
- (B) R2IK2
- (C) R22!K2
- (D) R22/K
- (A) leakage reactance
- (B) per unit impedance
- (C) efficiencies
- (D) ratings
- (A) voltage device
- (B) current device
- (C) power device
- (D) main flux device
- (A) to provide coupling between primary and secondary
- (B) to increase the magnitude of mutual flux
- (C) to decrease the magnitude of mag-netizing current
- (D) to provide all above features
- (A) less will be the secondary induced e.m.f.
- (B) less will be the primary induced e.m.f.
- (C) less will be the primary terminal voltage
- (D) none of the above
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