FeO (s) + CO (g) = Fe (s) + CO2 (g), k = 0. 435 at 1173E; at equilibrium, what will be the number of moles of CO gas required to reduce one mole of FeO at 1173 K ?

Chemical Engineering Mcqs

FeO (s) + CO (g) = Fe (s) + CO2 (g), k = 0. 435 at 1173E; at equilibrium, what will be the number of moles of CO gas required to reduce one mole of FeO at 1173 K ?

(A)  1.0

(B)  1.3

(C)  2.3

(D)  3.3



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